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Y=x^2-3x-10- Show all of your steps y=x^22x **y=x^22x (2/2)^2=1 1=answer** y=3x **y=3x (3/2)^2=225 225=answer** am i right or wrong, if im wrong could someone show me the steps trigonometric functions Solve and state the general solution for all values of x in exact form Show all steps algebraically sin^2 𝑥 − √2 cos 𝑥 = cos^2 𝑥Y= x^2 3x 18 We need to find the xintercept of the curve y The xintercept is the point where the curve y meets the xaxis Then the values of y would be zero



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Let's graph y=x 2 x c for different values of c (note our a = b =1) Here is the graph of y=x 2x (blue), x 2x2 (red), x 2x ½ (green), x 2x3 (purple) Notice that the c is the yintercept of each graph What do you think the graph of y=¼x 2 3x1 will look like? Explicación paso a paso3x12=x23xx=1222x=10x=5 gracias bro voy a publicar mas preguntas habee sis que md las puedas responder podesΔ = b 24ac Δ = 3 24·(1)·(1) Δ = 5 The delta value is higher than zero, so the equation has two
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Y = x 2 3x 8 y is the dependent variable and is given in terms of the independent variable x Note that y is the subject of the formula Implicit functions, on the other hand, are usually given in terms of both dependent and independent variablesY=x^23x6 Answer by Edwin McCravy() (Show Source) You can put this solution on YOUR website!{x 2 y 2 = 9 2xy;




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DEFINITION A differential equation is separable if it is of the form y'=f (x,y) in which f (x,y) splits into a product of two factors, one depending on x alone and the other depending of y alone Thus each separable equation can be expressed in the form y'=Q (x)R (y), where Q and R are given functions When R (y)0 we can divide by R (y) andCompute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, historyY=x2;y=3x2 Simple and best practice solution for y=x2;y=3x2 Check how easy it is, to solve this system of equations and learn it for the future Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework If it's not what You are looking for type in the system of equations solver your own




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Find the shortest distance between the line y = x – 2 and the curve y = x^2 3x 2 asked in Limit, continuity and differentiability by SumanMandal (546k points) the tangent and normal;Y = x^3 x, y = 3xSketch the region enclosed by the given curves Decidewhether to integrate with respect to x or y Draw a typical approximatingrectangle a Example 2 y = x 2 − 2 The only difference with the first graph that I drew (y = x 2) and this one (y = x 2 − 2) is the "minus 2" The "minus 2" means that all the yvalues for the graph need to be moved down by 2 units So we just take our first curve and move it down 2 units Our new curve's vertex is at −2 on the yaxis




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Calculadoras gratuitas paso por paso para álgebra, Trigonometría y cálculo Ex 25, 9 Verify (i) x3 y3 = (x y) (x2 – xy y2) Ex 25, 9 Verify (ii) x3 y3 = (x y) (x2 xy y2) LHS x3 y3 We know (x y)3 = x3 y3 3xy (x y The derivative of cos^3(x) is equal to 3cos^2(x)*sin(x) You can get this result using the Chain Rule which is a formula for computing the derivative of the composition of two or more functions in the form f(g(x)) You can see that the function g(x) is nested inside the f( ) function Deriving you get derivative of f(g(x)) > f'(g(x))*g'(x) In this case the f( ) function is the cube or




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Подставляем х из первого уравнения во второе и находим y (7 y) 2 y 2 = 9 2y (7 y);Algebra Calculator is a calculator that gives stepbystep help on algebra problems See More Examples » x3=5 1/3 1/4 y=x^21 Disclaimer This calculator is not perfect Please use at your own risk, and please alert us if something isn't working Thank youSolving x 23x28 = 0 directly Earlier we factored this polynomial by splitting the middle term let us now solve the equation by Completing The Square and by using the Quadratic Formula Parabola, Finding the Vertex 31 Find the Vertex of y = x 23x28 Parabolas have a highest or a lowest point called the Vertex




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Algebra Graph y=x^23x4 y = x2 3x − 4 y = x 2 3 x 4 Find the properties of the given parabola Tap for more steps Rewrite the equation in vertex form Tap for more steps Complete the square for x 2 3 x − 4 x 2 3 x 4Well from our discoveries, we can say that the graph will open downGet stepbystep solutions from expert tutors as fast as 1530 minutes Your first 5 questions are on us!




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Solution for Y=x23x1 equation =Y23Y1 We move all terms to the left(Y23Y1)=0 We add all the numbers together, and all the variables(Y^23Y1)=0 We get rid of parenthesesY^23Y1=0 We add all the numbers together, and all the variables1Y^23Y1=0 a = 1;Y >1/2 x yAll equations of the form a x 2 b x c = 0 can be solved using the quadratic formula 2 a − b ± b 2 − 4 a c The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction x^ {2}3xy6=0 x 2 3 x − y − 6 = 0 This equation is in



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Calculadoras gratuitas passo a passo para álgebra, trigonometria e cálculo y 2x = 3xy 2 2 = 3x 2y = 3x 2 this is the slopeintercept form of the equation of the line, y = mx b, where slope m is 3, and the yintercept b isY = 3x and y = x2insqunits3x = x2x = 3andx= 0 are the points of intersection0∫ 3 (3x−x2)dx= 23x2 ∣03 − 3x3 ∣03 = 329 − 327 = 227 −9= 29 = 45sq units




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Multiply 4 4 by 1 1 Subtract 9 4 9 4 from 0 0 Substitute the values of a a, d d, and e e into the vertex form a ( x d) 2 e a ( x d) 2 e Set y y equal to the new right side Use the vertex form, y = a ( x h) 2 k y = a ( x − h) 2 k, to determine the values of a a, h h, and k kAnswer to For the function, find the points on the graph at which the tangent line is horizontal If none exist, state that fact \\ y=x^23x2Sin (x)cos (y)=05 2x−3y=1 cos (x^2)=y (x−3) (x3)=y^2 y=x^2 If you don't include an equals sign, it will assume you mean " =0 " It has not been well tested, so have fun with it, but don't trust it If it gives you problems, let me know Note it may take a few seconds to finish, because it has to do lots of calculations



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Click here to see ALL problems on Graphs Question graph y=2/3x1 Found 2 solutions by jim_thompson5910, cutecherry Answer by jim_thompson5910 () ( Show Source ) You can put this solution on YOUR website!So for that, we have to find the critical value of y so, differentiate y respect to x y′ = 3x2 −6x = 3x(x−2) = 0 So, X is either be 2 or 0 these are the critical valuesY= x^33x^26 given function differentiate wrt x dy/dx = 3x^2 6x again differentiate wrt x d^2y/dx^2 = 6x 6 Find the maximum and minimum values, put dy/dx = 0 3x^2 6x = 0 3x(x2) = 0 x =0, x=2 when x=0, y= 6 and x = 2, y = 2 Hence the maxim



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Y=x2 (1,1) (4,2) Figure 2 The area between x = y2 and y = x − 2 split into two subregions If we slice the region between the two curves this way, we need to consider two different regions Where x > 1, the region's lower bound is the straight lineLooking at we can see that the equation is in slopeintercept form where the slope is and the yintercept is




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